Q.4. In the figure, ALMN is an isosceles right angled
triangle. LM = MN, MXM = 90°
L
H
H
N
M
Write the following trigonometric ratios. (i) sin N
(ii) tan L (iii) cos N (iv) tan N
Q.5. In the figure given below, ZDGE = 90°,
DGF = 90°, ZEDG = 60°, ZDFG = 50°
Answers
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Answer:
Given: △ABC, AB=BC=x, ∠ABC=90
∘
By Pythagoras Theorem,
AC
2
=AB
2
+BC
2
AC
2
=x
2
+x
2
AC
2
=2x
2
AC=
2
x
Since, AB=BC, then by Isosceles triangle property,
∠ACB=∠CAB=45
∘
Now, Sin45
∘
=SinC=
H
P
=
AC
AB
=
x
2
x
=
2
1
so, the value of m is =2
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