Question

Q.4 The charges and coordinates of
two charged particles held fixed in an
xy plane are q1=+3.0 mc, x1 = 3.5 cm,
y1 = 0.50 cm,and q2=-4.0 mc,
X2=-2.0 cm, y2 = 1.5 cm. At what x
and y coordinates should a third
particle of charge q3=+4.0 mc be
placed such that the net electrostatic
force on particle 2 due to particles 1
and 3 is zero? (A) -8.4 cm, 2.7 cm (B)​

Answer 1

Answer:

1) First of all, we need to find the distance between the two charges. Their distance on the xy plane is

substituting the coordinates of the two charges, we get

2) Then, we can calculate the electrostatic force between the two charges  and , which is given by

where  is the Coulomb's constant.

Substituting numbers, we get 

and the negative sign means the force between the two charges is attractive, because the two charges have opposite

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Explanation: