Question

' ☟︎︎︎ ☟︎︎︎

✍️ꜱᴜᴍ ᴏꜰ ᴛʜᴇ ᴀʀᴇᴀꜱ ᴏꜰ ᴛᴡᴏ ꜱQᴜᴀʀᴇꜱ ɪꜱ 468 ${ᴍ}^{2}$. ɪꜰ ᴛʜᴇ ᴅɪꜰꜰᴇʀᴇɴᴄᴇ ᴏꜰ ᴛʜᴇɪʀ ᴘᴇʀɪᴍᴇᴛᴇʀꜱ ɪꜱ 24 ᴍ, ꜰɪɴᴅ ᴛʜᴇ ꜱɪᴅᴇꜱ ᴏꜰ ᴛʜᴇ ᴛᴡᴏ ꜱQᴜᴀʀᴇꜱ.
⭐⭐ ...
⚠️⚠️Wrong Answer will be reported...​

Answer 1

Answer:

12 m

18 m

Step-by-step explanation:

Given that,

Sum of areas of two squares is 468 sq. m

Also, given that,

The difference of their perimeter is 24 m.

To find the sides of squares.

Let, the sides of squares be x m and y m respectively.

Therefore, we have,

=> x^2 + y^2 = 468 .......(1)

And,

=> 4x - 4y = 24

=> 4(x - y) = 24

=> x - y = 24/4

=> x - y = 6

=> x = y+6

Substituting this value in eqn (1), we get,

=> (y+6)^2 + y^2 = 468

=> y^2 + 6^2 + 2(y)(6) + y^2 = 468

=> 2y^2 + 36 + 12y -468 = 0

=> 2y^2 + 12y -432 = 0

=> 2y^2 + 36y - 24y - 432 = 0

=> 2y(y+18) - 24(y + 18) = 0

=> (y+18)(2y-24) = 0

Therefore, we have,

=> y + 18 = 0

=> y = -18

And

=> 2y - 24 = 0

=> 2y = 24

=> y = 24/2

=> y = 12

But, side can't be negative.

Therefore, we have,

=> y = 12

Therefore, we will get,

=> x = 12+6

=> x = 18

Hence, the sides of squares are 12 m and 18 m

Answer 2

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