Question

Q 49 . An aero plane flying horizontally with the speed of 320ft/sec releases a bomb at a height of
2304ft. the time taken by the bomb to reach the ground is
a) 7 sec
b) 10sec
c) 12 sec
d) 24sec​

Answer 1

Answer:

The aeroplane has a speed in the horizontal direction and there no component in the vertical direction. SO, the bomb will drop from rest and move under the action of gravity.

The initial speed of bomb is 0 m/s.

The acceleration of the bomb is 9.8 m/s

2.

The distance through which the bomb falls is 78.4 m.

The time taken by the bomb to fall to the ground is given by:

S=ut+ 21at 278.4=0+ 21 ×9.8×t2

t= 9.878.4×2

= 16

= 4 s

Explanation:

Hope it helps u!