Q: 5 [3]
A block of mass 0.8kg is dragged along a level
surface at constant velocity by a hanging block of
mass 0.2kg as shown in figure. Find tension in the
string and acceleration of the system, if the
coefficient of friction between the block and the
surface is 0.045.
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Answer:Let m₁ = 0.8kg
m₂ = 0.2 kg
Acceleration = m₂g / (m₁ + m₂)
g = 9.8 m/s²
m₂g = 0.2 × 9.8 = 1.96
a = 1.96/1 = 1.96 m/s²
Ft = m₁a
Tension = 0.8 × 1.96 = 1.568 N
Explanation:
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