Q.5
A bus started its journey at a speed of 50 km/hr. and reached at different stations. Its entire
journey is shown below.
(2)
B
500 km
400 km
с
WOOC
300 km
E
600 kom
Answers
You missed the attachment so I'm adding the bus journey picture.
i) The total distance covered by the bus from A to D
= (4170 + 3410 + 2160) km
= 9740 km
ii) The total distance covered by the bus from D to G
= (8140 + 4830 + 2550) km
= 15520 km
iii) The total distance covered by the bus, if it starts from A and returns back to A
= (4170 + 3410 + 2160 + 8140 + 4830 + 2550 + 1290) km
= 26550 km
iv) The difference of distances from C to D and D to E
= (8140 - 2160) km
= 5980 km
v) Speed of the bus = 60 km/h
Time taken = (Distance)/60 hours
a) The distance between A to B
= 4170 km
Time taken
= 4170/60 hours
= 4170/60 × 60 minutes
= 4170 minutes
= (60 × 69) + 30 minutes
= 69 hours 30 minutes
b) The distance between C to D
= 2160 km
Time taken
= 2160/60 hours
= 36 hours
c) The distance between E to G
= (4830 + 2550) km
= 7380 km
Time taken
= 7380/60 km
= 123 hours
d) Total journey
= 26550 km
Time taken
= 26550/60 hours
= 442.5 hours
= 442 hours 30 minutes
Answer:
A bus started its journey and reached different places with a speed of 60 km/hour. The journey is shown in given figure.
Find the total distance covered by the bus, if it starts from A and returns back to A.

Easy
Answer
Total distance travelled:-
AB+BC+CD+DE+EF+FG+GA
=4170+3410+2160+8140+4830+2550+1290
=26,550km.