Question

Q.5.A cricketer throws a ball at an
angle of 30° with the horizontal
having velocity 30ms-! The maximum
height attained by the ball is(Take g =
10 ms-2) *
O (a) 40.25m
O (b) 20.50m
O (c) 11.25 m
O d
(d) 50 m​

Answer 1

Answer:

(c)11.25

Explanation:

Hmax =u²sin²theta/g

30*30*1/4÷10

=45÷4

=11.25