Question

Q 5 aaur Q6 ka ans chaiye steps ke saath​

Answer 1

Answer:

Q.5th angle BAP=56

angle ADP=45

Step-by-step explanation:

BPC=APD......OPPOSITE ANGLES

APD+APB=180.......ANGLES IN LINEAR PAIR

124+APB=180

APB=180-124

APB=56

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ABCD IS A RECTANGLE THEREFORE ALL SIDES ARE 90°

AC AND BD SRE TRANSVERSAL

THEREFORE ANGLE BISECTOR THEOREM

ADC=2ADP

90 = 2ADP

90/2=ADP

45°=ADP

Q.6......

Given that ABCD is a rhombus with diagonal AC and <CAD = 38°.

We need to find :-

(1) <ACB

As we know that in a rhombus opposite angles are equal

=> <DAB = <DCB

Also the diagonal of a rhombus bisects the angles .

So , <DAC = <CAB = 38°.

=> <ACB = <DAC = 38°. (alternate angles)

(2) <DAC

As proved above that <DAC = <CAB = 38°.

(3) <ADC

As said above that in a rhombus opposite angles are equal .

So <CBA = <ADC

We know that <DAC + <CAB = <DAB

= 38° + 38° = 76°.

As AB || CD and AD and BC are transversal,

<DAB + <CBA = 180° ( co-interior angles)

= 76° + <CBA = 180°

= <CBA = 180° - 76°

=> <CBA = 104°.