Question

Q.5. Factorize:
(1) 4x² + 4x + 1​

Answer 1

$\texttt{Using middle term split }$

$\mathtt{\;\;\;\; 4x²+4x+1}$

$\mathtt{= 4x²+2x+2x+1}$

$\mathtt{= 2x(2x+1)+1(2x+1)}$

$\mathtt{= (2x+1)(2x+1)}$

$\texttt{Or}$

$\texttt{Using the formula (a+b)²=a²+2ab+b²}$

$\mathtt{\;\;\;4x²+4x+1}$

$\mathtt{= (2x)²+2×2x×1+(1)²}$

$\mathtt{= (2x+1)²}$

$\mathtt{= (2x+1)(2x+1)}$

Answer 2

Answer:

Given:4x²+4x+1

=4x²+2x+2x+2

=(4x²+2x)+(2x+1)

=(2x+1)(2x+1)

=(2x+1)

Second method

(a+b²)=a²+2ab+b²

=4x²+4x+1

=(2x²)+2*2x+1²

(2x+1)²