Question

Q.5 Find the interest on Rs 1200 at 5% per annum for 146 days. * 3 points Rs 36 Rs 28 Rs 24​

Answer 1

$\large\underline{\sf{Solution-}}$

Given that,

• Principal, P = Rs 1200

• Rate of interest, r = 5 % per annum

• Time, n = 146 days = 146/365 = 2/5 years

We know,

Simple interest ( SI ) received on a certain sum of money of Rs P invested at the rate of r % per annum for n years is given by

$\boxed{ \rm{ \: \:SI \: = \: \dfrac{P \times r \times t}{100} \: \: }}$

So, on substituting the values, we get

$\rm \: SI \: = \: 1200 \times \dfrac{5}{100} \times \dfrac{2}{5}$

$\bf\implies \:\boxed{ \bf{ \:SI \: = \: Rs \: 24 \: \: }}$

$\rule{190pt}{2pt}$

Additional Information :-

$\begin{gathered}\: \: \: \: \: \: \begin{gathered}\begin{gathered} \footnotesize{\boxed{ \begin{array}{cc} \small\underline{\frak{\pmb{ \red{More \: Formulae}}}} \\ \\ \bigstar \: \bf{P = \dfrac{SI \times 100}{r \times n} }\\ \\ \bigstar \: \bf{r = \dfrac{SI \times 100}{P \times n} }\\ \\ \bigstar \: \bf{n = \dfrac{SI \times 100}{P \times r} }\\ \\ \bigstar \: \bf{Amount = P\bigg(\dfrac{100 + rn}{100} \bigg) }\: \end{array} }}\end{gathered}\end{gathered}\end{gathered}$

Answer 2

Answer:

₹24

Step-by-step explanation:

$\large \bold{\sf{Solution \rightarrow}}$

$\large\underline{\sf{Given \rightarrow}}$

$\large\underline{\sf{♣principal = Rs.1200♣}}$

$\large\underline{\sf{ \dag Rate \rightarrow \: 5\% \: per \: annum \dag}}$

$\large\underline{\sf{➡Time \rightarrow \frac{146}{365} = \frac{2}{5} of year}}$

According to information we have to find amount after 146 days.

First know what is simple interest:-

Simple interest is a quick and easy method of calculating the interest charge on a loan.

$\large\underline{\sf{Formula \: for \: simple \: interest}}$

$\large\underline{\sf{Si = \frac{p \times r \times t}{100} }}$

On substituting values we get,

$\large{\sf{ \implies\frac{1200 \times 2 \times 5}{5 \times 100} }}$

$\large\underline{\bf{ \implies Rs.24}}$