Question

Q.5.lf a^2+ b^2 = 119 and ab = 1, then

find the value of:

(ii) (a + b)^2


please answer step by step​

Answer 1

Answer:

hope it helps you.......

Answer 2

Given a^2 + b^2 = 119-----(1) , ab = 1 ----(2)

then (a+b)^2 = a^2 + b^2 + 2ab

= 119 + 2(1) { ∵ From eq(1)&eq(2) }

= 119 + 2 = 121

∴ ( a + b ) ^2 = 121