Question

Q.5.
Solve any one subquestion from the following.
1) Given: O is the centre of
circle.
angleBCO= mº. angleBAC= n degree
Find: The value of m+n​

Answer 1

$\bf m + n = \frac{180 \degree - \angle BOC}{2} + \frac{1}{2} \angle BOC \\ \\ \sf = > \frac{1}{2} (180 \degree - \cancel{\angle BOC} + \cancel{\angle BOC}) \\ \\ = > \frac{1}{2} \times 180 \degree = \red{90 \degree}$

Answer 2

Answer:

Angle BOC= 2n( angle subtended from the centre thaving same points on circle is half of the angle on centre)

angle OBC= m (OC and OB are radii and it is isosceles∆)

Angle BOC+ Angle m+ angle OBC= 180°

2n + m+m=180°

2n+2m= 180°

2(m+n)= 180°

m+n= 90°

Step-by-step explanation:

hope it helps..