Question

Q.5. The gas burns in oxygen as follow:
2h2s + 3O2 ----> 2h20 + 2SO2
Calculate the standard enthalpy change for this reaction using standard enthalpies of formation.
The ∆HF
2h2s(g)= - 20.5kj/mol
302(g)=0 kJ/mol
2H20(1)=285.8 kJ/mol
250.(g)-296.8 kl/mol
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Answer 1

$</p><p>The first thing to do here is write a balanced chemical equation for this reaction</p><p></p><p>2</p><p>H</p><p>2</p><p>S</p><p>(g]</p><p>+</p><p>3</p><p>O</p><p>2(g]</p><p>→</p><p>2</p><p>SO</p><p>2(g]</p><p>+</p><p>2</p><p>H</p><p>2</p><p>O</p><p>(l]</p><p> </p><p></p><p>SInce the standard enthalpy change of reaction, </p><p>Δ</p><p>H</p><p>∘</p><p>rxn</p><p> , for this reaction was not provided, you're going to have to calculate it using standard enthalpies of formations</p><p>$