Question

Q.53. Total number of atoms present in 34 g of NII, is
A) 4x1023
B) 4.8 x 1021
C) 2x 1023
D) 48 x 1023​

Answer 1

Answer:

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Explanation:

answer@

B)

4.8*1021

Answer 2

Answer:

option D is correct

Explanation:

Mass of 1 mol or (6.022×1023 molecules) of NH3=14+3×1=17 g

Number o f molecules in 34 g NH3=1734×6.022×1023=12.044×1023

Number of atoms present in 1 molecule of NH3=4

Number of atoms in 34 g NH3=4×12.044×1023

                                                      ≈48×1023