Question

Q 57 Find the efficiency of transmission if 10kW of power at 200 V is delivered to a company using an electric cable with resistance of 0.4 12.
Ops: A. О 91%
B. O 97%
C. 0 95%
О 99%
​

Answer 1

Answer:

Power P=VI

⇒I= V/P =

10×10-3/200=50A

∴ Power loss =I-2R=(50) 2×(0.2)=500W

Therefore, efficiency of transmission =

10000+500

10000×100

Answer 2

Explanation:

Given things are

P = 10000 W

V = 200V

R = 0.412

Finding Current

P = VI

I = $\frac{P}{V}$

= $\frac{10000}{200}$

= 50A

Power loss = $I^{2}R$

$50^{2}$ x 0412 = 1030 W

Finding efficiency

$\frac{(10000)(100)}{10000 + 1030}$ = 90.66%

Approx answer is 91%