Question

Q.6
54.4 gm [Fe(H,2O)5 NO]SO,4 contains
(A) 3.2 gm oxygen
(B) 32 gm of oxygen
(C) 6.4 gm of oxygen
(D) 64 gm of oxygen​

Answer 1

Answer:

★ Atomic Weights of

S Sulfur 32.065

O Oxygen 15.9994

Fe Iron 55.845

N Nitrogen 14.0067

H Hydrogen 1.00794

★ Molar mass of [Fe(H2O)5NO]SO4 is 271.9901 g/mol

Now You can Calculate Molar Mass of Oxygen indulge in it .

Answer 2

54.4 gm of $[Fe(H_{2} O)_{5} NO]SO_{4}$ contains (B) 32 gm of oxygen

$[Fe(H_{2} O)_{5} NO]SO_{4}$

Atomic mass of:

Iron(Fe)= 55.845 gm

Hydrogen(H) = 1.00784 gm

Nitrogen(N) = 14.0067 gm

Sulphur(S) = 32.065 gm

Oxygen(O) = 16 gm

So, the mass of $[Fe(H_{2} O)_{5} NO]SO_{4}$ = 271.9901 gm and mass of oxygen in this compound = (16 × 10)= 160 gm

So, 271.9901 gm of $[Fe(H_{2} O)_{5} NO]SO_{4}$ contains 160 gm of Oxygen

∴ 54.4 gm of $[Fe(H_{2} O)_{5} NO]SO_{4}$ contains $\frac{160}{271.9901}$ × 54.4  gm of Oxygen

                                                                 ⇒ 32 gram of Oxygen

So, 54.4 gm of $[Fe(H_{2} O)_{5} NO]SO_{4}$ contains (B) 32 gm of oxygen

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