Q. 6.(a) Cricket ball, a tennis ball and a proton which has more uncertainity.
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Explanation:
m=150×10
−3
kgΔx=10
−10
A
0
h=planck's constant
Using Heisenburg Uncertainity Principle
Δx.mΔv≥
4π
h
Δv=
4πmΔx
h
Δv=
4×3.14×10
−10
×0.15
6.626×10
−34
=3.5×10
−24
ms
−1
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