Question

Q. 6] From a point in the cricket ground ,the angle of elevation of a vertical tower is found to be theta (Ꝋ) at a distance of 200 from the tower. On walking 125 metre towards the tower the angle of elevation becomes 2 Ꝋ, find the height of tower ? प्र.6] क्रिकेटच्या मैदानावरील एका बिंदूपासून पाहिले असता एका उभ्या टॉवरचा टॉवर पासून 200 मी अंतेरवरील बिन्दुशी होणारा उन्नत कोन Ꝋआहे . टॉवरच्या दिशेने 125 मी चालले असता उन्नत कोन 2 Ꝋ होतो ,तर टॉवरची उंची काढा . *

a)300m
b)100m
c)400m
d)200m​

Answer 1

Answer:

fridge freezer and a few other items that have a good night out in a small bowl are not hope

Answer 2

Answer:

Thus the height of tower=100 m

Step-by-step explanation:

In the Δ PQA

tan θ =PQ/QA

or tan θ= h/200

h=200*tanθ.................(1)

In the Δ PQB

tan 2θ =PQ/QB=h/(200-125)

2tanθ/(1- tan²θ) =h/75

From(1) putting value of h

2tanθ/(1- tan²θ) =200*tanθ/75

1 /(1-tan²θ) =100/75=4/3

4*( 1-tan²θ)=3

1-tan²θ =3/4

tan²θ =1-3/4=1/4

tan θ =1/2

Thus from (1)

h=200*1/2=100

Thus the height of tower=100 m