Question

Q.6. If a 1 gallon bottle were filled with bleach (NaClO), how many
Cl atoms would be in the bottle? ρbleach = 1.090 g/mL, (1 gallon
= 3.785 L)

Answer 1

Total 344.4636*10^23 Cl atoms would be present in the bottle

• As ρbleach = 1.090 g/mL then there exists 1.09 grams of bleach per mL of solution. The bottle was filled with 1 gallon bleach.
• Now 1 gallon = 3.785 L = 3785 mL . So amount of bleach present in the bottle = 1.090*3785 = 4125.65 grams.
• Now in NaClO the ratio of weights of atoms = 23 : 35.5 : 16. So amount of Cl present in bleach = $4125.65 *\frac{35.5}{23+35.5+16}$ = 1966 grams.
• Now 1966 grams Cl  = $\frac{1966}{35.5} =$ 55.38 mole of Cl
• Now we know 1 mole of Cl contains 6.22*10^23 atoms.
• So total number of Cl atoms = $55.38*6.22*10^{23} = 344.4636 *10^{23}$