Math, asked by paramveer244, 11 months ago

Q 60. Ajay can do a piece of work in 10 days and Harshal can do same work in 12 days.
They started working together but Ajay left the work 2 days before completion of work, then
time taken to complete the work?​

Answers

Answered by amitnrw
2

Given : Ajay can do a piece of work in  10 days and Harshal can do same work in  12 days.

They started working together but  Ajay left the work 2 days before

completion of work

To Find : how much time  taken to complete the work?​

Solution:

Ajay can do a piece of work in  10 days

Ajay 1 day work = 1/10

Harshal can do a piece of work in  12 days

Harshal 1 day work = 1/12

Their 1 day work = 1/10 + 1/12  =  11/60

Their n days work = n * 11/60

Last 2 Days work by Harshal = 2 (1/12)  = 1/6

Remaining work done by both = 1 - 1/6   = 5/6

n * 11/60  = 5/6

=> n = 50/11

=> n =  4.545  

Total time Taken = 4.545 + 2 = 6.545 Days

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