Q 61.....plz hlp need fast...thnx
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Given that Total number of balls = 5.
Total Number of persons = 3.
Given that Each person gets at least one ball.
Possible combinations are (1,1,3) and (2,2,1).
When (1,1,3) balls are distributed to each person, The total number of ways =
= 5!/1!1!3! * 1/2! * 3!
= 60.
When (2,2,1) balls are distributed to each person, The total number of ways =
= 5!/1!2!2! * 1/2! * 3!
= 90.
The required number of ways = 60 + 90 = 150.
Hope this helps!
Total Number of persons = 3.
Given that Each person gets at least one ball.
Possible combinations are (1,1,3) and (2,2,1).
When (1,1,3) balls are distributed to each person, The total number of ways =
= 5!/1!1!3! * 1/2! * 3!
= 60.
When (2,2,1) balls are distributed to each person, The total number of ways =
= 5!/1!2!2! * 1/2! * 3!
= 90.
The required number of ways = 60 + 90 = 150.
Hope this helps!
Neerav34:
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i gt the first step
311 n 221
bt aftr tht
from the 5th line frm above
plz xplain
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