Math, asked by sakshi1998sj, 11 months ago

Q. 7.
Cost price of 6 'Dairy Milks' is equal to the selling price of 10 'Kitkats' and cost price of 6 Kitkats' is equal to the selling price of 1 'Dairy Milk'. Net profit percent on the sale of a 'Dairy Milk' and a Kitkat' is 50%. Find the profit percentage on the sale of each 'Kitkat'.[Assume all 'Dairy Milks' are identical and the same applies to 'Kitkats'.]

Answers

Answered by amitnrw
5

Answer:

200% on KitKat

20% on Dairy Milk

Step-by-step explanation:

Let say cost price of KitKat  = K rs

Cost Price of 6 kitkats = 6K Rs

Selling Price of 1 dairy Milk = 6K Rs

Cost Price of 1 Dairy Milk = D  Rs

Cost Price of 6 dairy Milk = 6D  Rs

Selling Price of 10 kitkat = 6D

=> Selling Price of Kitkat = 0.6D

Cost Price of 1 kitkat + 1 Dairy milk = K + D  Rs

Selling Price of 1 KitKat + 1 Dairy Milk = 6K + 0.6D  Rs

Profit = 6K + 0.6D - K - D  = 5K - 0.4D  Rs

Profit = 50 %

=> (5K - 0.4D)/(K + D) = 50/100

=> 10K - 0.8D = K + D

=> 9K = 1.8D

=> D = 5k

cost price of KitKat  = K

Selling Price of Kitkat = 0.6D  = 0.6*5K  = 3K

Profit = 2K

Profit % = (2K/K) * 100 = 200%

Cost Price of Dairy Milk = D = 5K

Selling Price of Dairy milk = 6K

Profit = 6K - 5K = K

Profit %  = (K/5K) * 100 = 20 %

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