Question

Q.7 Find the zeroes of the quadratic polynomial x

2

-2x-8 and verify the relationship between the zeroes

and the coefficients.​

Answer 1

Step-by-step explanation:

x²-2x-8 =ax²+bx+c

x²-4x+2x-8=0 a= 1

x(x-4)+2(x-4) b= -2

(x-4)(x+2) c= -8

x-4=0 ,x+2=0

x=4 ,x= ‐2

alpha=4,beta= -2

Relationship between zeroes and polynomial

Sum of zeroes =alpha +beta= –b/a

4+(-2) = -(-2)/1

4-2 =2/1

2 = 2

Product of zeroes= alpha ×beta =c/a

4×-2 = -8/1

-8 = -8

Therefore Hence verified