Q.71
For the reaction
2A + 3B + 5C → 3D
Initially if 2 mole of A, 4 mole of B and 6
mole of C is taken, With 25% yield, moles
D which can be produced are
(1) 0.75
(3) 0.25
(2) 0.5
(4) 0.6
Answers
Answer: The correct answer is Option 1.
Explanation:
We are given:
Moles of A = 2 mole
Moles of B = 4 mole
Moles of C = 6 mole
For given a chemical equation:
By Stoichiometry of the reaction:
2 moles of A reacts with 3 moles of B and 5 moles of B.
So, 2 moles of A reacts with of B and of C.
As, the given amount of B and C is more than the required amount. Thus, it is present in excess and is considered as an excess reagent.
Therefore, A is considered as limiting reagent because it limits the formation of products.
By Stoichiometry of the reaction:
2 mole of A is producing 3 moles of D.
So, 2 moles of A will produce of D.
To calculate the experimental yield of D, we use the equation:
% yield of reaction = 25 %
Theoretical yield of D = 3 moles
Putting values in above equation, we get:
Hence, the correct answer is Option 1.
Answer:
Answer: The correct answer is Option 1.
Explanation:
We are given:
Moles of A = 2 mole
Moles of B = 4 mole
Moles of C = 6 mole
For given a chemical equation:
By Stoichiometry of the reaction:
2 moles of A reacts with 3 moles of B and 5 moles of B.
So, 2 moles of A reacts with of B and of C.
As, the given amount of B and C is more than the required amount. Thus, it is present in excess and is considered as an excess reagent.
Therefore, A is considered as limiting reagent because it limits the formation of products.
By Stoichiometry of the reaction:
2 mole of A is producing 3 moles of D.
So, 2 moles of A will produce of D.
To calculate the experimental yield of D, we use the equation:
% yield of reaction = 25 %
Theoretical yield of D = 3 moles
Putting values in above equation, we get:
Hence, the correct answer is Option 1.