Question

Q.8 In triangle ABC,angle ABC=90
degree and BD perpendicular to CD,
if BD = 8 cm. AD = 4 cm then x = CD
will be---​

Answer 1

➛ Sσlutíσn :

Let ∠ACB = x, ∠ABD = x, ∠CBD = 90-x° and

∠BAD = 90-x°

ΔABC , ΔABD and ΔBDC are similar,

$\implies$ $\displaystyle{\sf{ \frac{BD}{CD} = \frac{AD}{DB}}}$

$\implies$$\displaystyle{\sf{ \frac{8}{CD} = \frac{4}{8}}}$

$\implies$ $\displaystyle{\sf{ CD = \frac{8 \times 8 }{4} = 16}}$