Question

Q.9
A voltage of resistance 500 2 can measure a maximum voltage 5v. How can it be made to measure
a maximum voltage of 100 volt.​

Answer 1

If you add a resistor of 500 ohms, you will be able to read 10 Volts actual as 5 volts measured. So to read 100 Volts actual as 5 volts measured, you need to add 10 x this as the total resistance value. So 1,000 x 10 = 10,000 ohms. The meter has an internal resistance of 500 ohms so we subtract that from the 10,000 ohms leaving 9,500 ohms. So we simply add a single resistor of 9,500 ohms or multiple resistors to add up to 9,500 ohms.

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Answer 2

The resistance required to make it measure a maximum voltage ( V ) of 100 volts is 9500 Ω.

Given: Resistance of Voltmeter ( G ) = 500 Ω

The maximum voltage of Voltmeter ( Vg ) = 5 V

To Find: Resistance required to make it measure a maximum voltage                          ( V ) of 100 volts.​

Solution:

• We know that to increase the range of the voltmeter by a particular factor, a resistance R should be connected in series with the voltmeter.
• The increased resistance R can be found using the formula,

                R = G ( ( V / Vg ) - 1 )

                where G = 500 Ω, V = 100 V, Vg = 5 V.

Using this formula and placing the values, we get,

                R = 500 ( ( 100 / 5 ) - 1 )

                   = ( 500 × 19 ) Ω

                   =  9500 Ω

Hence, the resistance required to make it measure a maximum voltage ( V ) of 100 volts is 9500 Ω.

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