Question

Q:9 An Isosceles triangle has perimeter 30 cm. and each of the equal sides is 12 cm. find the area of the
triangle.​

Answer 1

Step-by-step explanation:

perimeter of an isosceles triangle = 30cm

length of equal sides = 12cm each

so, sum of length of equal side =12+12=24cm

length of another side = 30 - (12+12)

=30-24=6cm

area of triangle =

$\sqrt{ s{(s - a)(s - b)(s - c)}}$

$= s = \frac{30}{2} = 15cm$

$= \: \: \: \: \: \: \: \sqrt{15(15 - 12)(15 - 12)(15 - 6) }$

$= \sqrt{15 \times 3 \times 3 \times 9}$

$= 9 \sqrt{15}$

$9 \times 3.873 \\ = 34.857 \: {cm}^{2}$

PLEASE MARK ME AS BRAINLIEST

Answer 2

Answer:

1215cm² is your ans. for your question