Question

Q.  A 2.0 cm tall object is placed perpendicular to the principal axis of a convex lens of focal length 10 cm. The distance of the object from the lens is 15 cm.  Find the nature, position and size of the image.  Also find its magnification.


Wrong answers will be reported..!​

Answer 1

H(o) = -2 cm

f = +10 cm

u = -15 cm

v = unknown

Nature = unknown

H(i) = unknown

Using the lens formula,

1/v - 1/u = 1/f

1/v - (-1/15) = 1/10

1/v = 1/10 - 1/15

1/v = 1/30

v = +30 cm

=> Image is formed at a distance of 30 cm at the back of the lens.

Magnification:

M = v/u = +30/-15 = -2

=> Magnification of the image formed is -2.

Also,

H(i)/H(o) = M

H(i)/-2 = -2

H(i) = 4cm

=> Size of the image is 4cm

Thus concluding,

Position = +30 cm

Nature = virtual ( magnification is -ve )

Size = 4cm = Enlarged ( magnification > 1 )

Answer 2

Answer:

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