Question

Q.A block of mass 0.2 kg is suspended from the ceiling by a light string.a second block of mass 0.3 kg is suspended from the first block through another string.find the tensions in the two strings .Take g=10m/s^2.

Answer 1

from the force diagram for the lower block , force equation is given as

T₂ = m₂ g

T₂ = (0.3) (10)

T₂ = 3 N

from the force diagram for the Upper block , force equation is given as

T₁ = m₁ g + T₂

T₁ = (0.2) (10) + 3

T₁ = 5 N

Answer 2

Answer:

Explanation:

From the free-body diagram of the 0.3 kg block, T = 0.3g ⇒ T= 0.3 × 10 = 3 N Now, from the free-body diagram of the 0.2 kg block, T1 = 0.2g + T ⇒ T1= 0.2 × 10 + 3 = 5 N ∴ The tensions in the two strings are 5 N and 3 N, respectively.Read more on Sarthaks.com - https://www.sarthaks.com/42344/a-block-of-mass-0-2-kg-is-suspended-from-the-ceiling-by-a-light-string-a-second-block-of-mass