Question

Q. A block of mass 9 Kg rests on a plane
making an angle of 160 with horizontal,
Determine the component of the weight normal
to the planAns.
A. 86.5N
B. 84.86 N
C. 24.34N
D. 24.8N​

Answer 1

Explanation:

A block of mass 9 Kg rests on a plane making an angle of 16 degree with horizontal. Determine the component of the weight normal to the inclined plane.

Answer 2

Answer:

Along the normal weight component is $84.86$ $N$. The correct option is B.

Explanation:

• In a free body diagram, the net forces along X-axis and Y-axis balance each other.
• The weight of the body acts along the vertical downwards direction.

The formula for the weight of the body is:

$W=M*g$

where, $M$ is the mass of the body.

            $g$ is the gravity.

Step 1:

Here, the mass of the block, $M=9$ $kg$

          gravity, $g= 10$ $m/s^{2}$

          angle with horizontal, θ $= 160^{0}$

As Component of weight normal to plane $= Mgcos$θ

Step 2:

So, the component of weight normal to the plane $=(9 kg)*(10 m/s^{2})cos160$

$=84.86$ $N$

So, the correct option is B.