Q-A bullet of 10 g strikes a sand-bag at a speed of 103 m/s and gets embedded after travelling 5 cm. Calculate the time taken by the bullet to come to rest -
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Answer:
Explanation:
v
2
=u
2
+2as
0=(10
3
)
2
+2×a×(5×10
−2
)
a=−10
7
m/s
2
v=u+at
0=10
3
−10
7
×t
t=10
−4
s
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