Math, asked by BRAINLYoficiall, 18 days ago

Ritika sold an electric iron for ₹4,725 at a loss of 10%. Find its cost price.

Answers

Answered by shivansh457
0

Answer:

C.P. = (100/100- loss% )× S.P.

C.P.= 100/100-10×4725

CP = 100/90×4725

now cancel one zero of 100 and 90

10/9×4725

now 9 will cancel 4725 by 525 times and then

to get the C.P. we have multiply 10 by 525

= 525×10 = 5250 rs

now we have to find loss = 5250-4725 = 525

loss% = loss×100/C.P = 525×100/5250

now 525 will cancel 5250 by 10 times

and to get the loss % we have to cancel 100/10 = 10 loss% = 10%.

Hence prooved.

Answered by qwvilla
0

Given: Selling price(S.P,)=  ₹4,725, Loss percentage(Loss%)= 10%

To find The value of the cost price (C.P.)

Solution: As Ritika suffers a loss percentage, we can say Ritika suffers a loss, then the selling price of the electric iron is less than that of the cot price of the electric iron.

Let the cost price of the electric iron be ₹x.

We can see when Ritika sells the electric iron, the selling price she gets is ₹4,725and that she achieves after the 10% loss of the cost price, so it can be written as:

 x-{10% of x}= 4725

⇒ x-{(10/100)×x} = 4725  [removing the percentage sign by dividing with 100]

⇒ x-(x/10)= 4725

⇒ (10x-x)/10 = 4725  [doing the L.C.M]

⇒ 9x = 4725×10

⇒ x=47250/9

⇒ x=5250

Hence the cost price(C.P.) of the electric iron is ₹5250.

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