Ritika sold an electric iron for ₹4,725 at a loss of 10%. Find its cost price.
Answers
Answer:
C.P. = (100/100- loss% )× S.P.
C.P.= 100/100-10×4725
CP = 100/90×4725
now cancel one zero of 100 and 90
10/9×4725
now 9 will cancel 4725 by 525 times and then
to get the C.P. we have multiply 10 by 525
= 525×10 = 5250 rs
now we have to find loss = 5250-4725 = 525
loss% = loss×100/C.P = 525×100/5250
now 525 will cancel 5250 by 10 times
and to get the loss % we have to cancel 100/10 = 10 loss% = 10%.
Hence prooved.
Given: Selling price(S.P,)= ₹4,725, Loss percentage(Loss%)= 10%
To find The value of the cost price (C.P.)
Solution: As Ritika suffers a loss percentage, we can say Ritika suffers a loss, then the selling price of the electric iron is less than that of the cot price of the electric iron.
Let the cost price of the electric iron be ₹x.
We can see when Ritika sells the electric iron, the selling price she gets is ₹4,725and that she achieves after the 10% loss of the cost price, so it can be written as:
x-{10% of x}= 4725
⇒ x-{(10/100)×x} = 4725 [removing the percentage sign by dividing with 100]
⇒ x-(x/10)= 4725
⇒ (10x-x)/10 = 4725 [doing the L.C.M]
⇒ 9x = 4725×10
⇒ x=47250/9
⇒ x=5250
Hence the cost price(C.P.) of the electric iron is ₹5250.