Question

Q A car travels at a uniform velocity of 60 m/s for 10 sec and is brought to rest in 5 sec . calculate the redardation of the car and the distance travelled in 15 sec?

Answer 1

u= 60 m/s
t = 10 sec
a =0
s= ut +(1/2)at²
 = 60×10  +0
 = 600 m
now, u = 60 m/s
v =0
t =5 sec
as, v= u+at
⇒0 = 60 + a×5
⇒5a = -60
⇒a = - 12 m/s²
also, s = ut +(1/2)at²
           = 60×5 +(1/2)×(-12)×(5)²
           = 150 m
 Total distance = 600+150 = 750 m

Answer 2

Answer:

a= -12m/s²

S(total distance)=750 m