Q)a convex lens forms a real image 4 times magnified at a distance of 60 cm from the lens.calculate the focal length & the power of lens??
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Hello ,
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●Given that,
m = -4 (Real image)
v = 60cm
●For lenses,
m = v/u = -4
So ,u= -60/4 = -15cm
●Now using the lens formula,
1/f = 1/v -1/u
=1/60-(-1/15) = 1/60 + 1/15
=5/60 = 1/12
So focal length f = 12cm = 0.12m
==> Power, P = 1/f = 1/0.12 = 8.3D. (Ans.)
__________________
HOPE IT HELPS U !!!
HAVE A WONDERFUL DAY AHEAD ☺☺
CHEERS ✌✌
# NIKKY
___________________
●Given that,
m = -4 (Real image)
v = 60cm
●For lenses,
m = v/u = -4
So ,u= -60/4 = -15cm
●Now using the lens formula,
1/f = 1/v -1/u
=1/60-(-1/15) = 1/60 + 1/15
=5/60 = 1/12
So focal length f = 12cm = 0.12m
==> Power, P = 1/f = 1/0.12 = 8.3D. (Ans.)
__________________
HOPE IT HELPS U !!!
HAVE A WONDERFUL DAY AHEAD ☺☺
CHEERS ✌✌
# NIKKY
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