Question

Q. A gas mixture contains 160 g O2 and 320 g O3. The molar ratio of O3 to O2 in the mixture will be ??

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Answer 1

Answer:

Mate your answer is 68g NH3.

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Answer 2

ANSWER

ANSWERMolar ratio of oxygen (O

ANSWERMolar ratio of oxygen (O 2

ANSWERMolar ratio of oxygen (O 2

ANSWERMolar ratio of oxygen (O 2 ) : nitrogen (N

ANSWERMolar ratio of oxygen (O 2 ) : nitrogen (N 2

ANSWERMolar ratio of oxygen (O 2 ) : nitrogen (N 2

ANSWERMolar ratio of oxygen (O 2 ) : nitrogen (N 2 ) =

ANSWERMolar ratio of oxygen (O 2 ) : nitrogen (N 2 ) = 32

ANSWERMolar ratio of oxygen (O 2 ) : nitrogen (N 2 ) = 321

ANSWERMolar ratio of oxygen (O 2 ) : nitrogen (N 2 ) = 321

ANSWERMolar ratio of oxygen (O 2 ) : nitrogen (N 2 ) = 321 :

ANSWERMolar ratio of oxygen (O 2 ) : nitrogen (N 2 ) = 321 : 28

ANSWERMolar ratio of oxygen (O 2 ) : nitrogen (N 2 ) = 321 : 284

ANSWERMolar ratio of oxygen (O 2 ) : nitrogen (N 2 ) = 321 : 284

ANSWERMolar ratio of oxygen (O 2 ) : nitrogen (N 2 ) = 321 : 284

ANSWERMolar ratio of oxygen (O 2 ) : nitrogen (N 2 ) = 321 : 284 ∴ Ratio of their molecules =

ANSWERMolar ratio of oxygen (O 2 ) : nitrogen (N 2 ) = 321 : 284 ∴ Ratio of their molecules = 32

ANSWERMolar ratio of oxygen (O 2 ) : nitrogen (N 2 ) = 321 : 284 ∴ Ratio of their molecules = 32N

ANSWERMolar ratio of oxygen (O 2 ) : nitrogen (N 2 ) = 321 : 284 ∴ Ratio of their molecules = 32N A

ANSWERMolar ratio of oxygen (O 2 ) : nitrogen (N 2 ) = 321 : 284 ∴ Ratio of their molecules = 32N A

ANSWERMolar ratio of oxygen (O 2 ) : nitrogen (N 2 ) = 321 : 284 ∴ Ratio of their molecules = 32N A

ANSWERMolar ratio of oxygen (O 2 ) : nitrogen (N 2 ) = 321 : 284 ∴ Ratio of their molecules = 32N A

ANSWERMolar ratio of oxygen (O 2 ) : nitrogen (N 2 ) = 321 : 284 ∴ Ratio of their molecules = 32N A :

ANSWERMolar ratio of oxygen (O 2 ) : nitrogen (N 2 ) = 321 : 284 ∴ Ratio of their molecules = 32N A : 28

ANSWERMolar ratio of oxygen (O 2 ) : nitrogen (N 2 ) = 321 : 284 ∴ Ratio of their molecules = 32N A : 284N

ANSWERMolar ratio of oxygen (O 2 ) : nitrogen (N 2 ) = 321 : 284 ∴ Ratio of their molecules = 32N A : 284N A

ANSWERMolar ratio of oxygen (O 2 ) : nitrogen (N 2 ) = 321 : 284 ∴ Ratio of their molecules = 32N A : 284N A

ANSWERMolar ratio of oxygen (O 2 ) : nitrogen (N 2 ) = 321 : 284 ∴ Ratio of their molecules = 32N A : 284N A

ANSWERMolar ratio of oxygen (O 2 ) : nitrogen (N 2 ) = 321 : 284 ∴ Ratio of their molecules = 32N A : 284N A

ANSWERMolar ratio of oxygen (O 2 ) : nitrogen (N 2 ) = 321 : 284 ∴ Ratio of their molecules = 32N A : 284N A ⇒7:32