Question

Q) A girl walks 200m towards east and then 150m towards north. The distance of the girl from starting point is
a)350
b)250
c)300
d)225​

Answer 1

Step-by-step explanation:

b) is correct answer

250 m is correct answer

Given : A girl walks 200m towards east and then 150m towards north.

Find starting point

Suppose

A girl Forming A triangle in which <B= 90°

By Phythogorus theroem we have

AC^2=AB^2+BC^2

AC^2=200^2+150^2

AC^2= 40000+22500

AC^2= 62500

AC= 250 m

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Answer 2

Given that:- A girl walks $200$ metre east and then $150$ metre north.

As we have to find that the distance from the starting point,

For that, we have to use the Pythagoras theorem

The required distance

$=\sqrt{(200)m^2+(150)m^2}$

$=\sqrt{40000+22500}$

$=\sqrt{62500}$

$=250m$

Hence, the required distance from the starting point is $250m.$