Question

Q. A mixture of 50.0 g of S and 100g of Cl2 reacts to form S2Cl2. the mass of S2Cl2 formed will be
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Answer 1

Answer:

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Answer 2

Concept:

A mole is the mass of a substance made up of an equal number of basic particles.

Given:

The mass of sulfur = 50.0 g

The mass of chlorine molecule  = 100 g

Find:

A mixture of 50.0 g of S and 100g of Cl₂ reacts to form S₂Cl₂. The mass of S₂Cl₂ formed will be?

Solution:

The reaction is as follows below.

                                S₂ + Cl₂ → S₂Cl₂

The molar mass of sulfur molecule = 64 g/mol

Chlorine molecules have a molar mass of 71 g/mol.

The molar mass of S₂Cl₂ = 135 g/mol

The number of moles of sulfur = 50.0 g / 64 g/mol = 0.78 mol

The number of moles of chlorine molecule = 100 g / 71 g/mol = 1.41 mol

The limiting reactant in this reaction is a sulfur molecule. So, 0.78 mole of sulfur molecule gives 0.78 moles of S₂Cl₂.

So, the mass of S₂Cl₂ = the number of moles * molar mass.

= 0.78 mol * 135 g/mol

= 105.3 g

Hence, the mass of S₂Cl₂ formed is 105.3 g.

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