Question

Q.) A paper is in the form of a rectangle PQRS in which PQ = 10cm and QR = 7cm . Two semi-circular portions with QR and PS as diameters are cut off ( As shown in figure 11.22 ) . Find the area of the remaining part .
You can see the figure in the attachment .

Answer it with step-by-step explanation .​

Answer 1

Step-by-step explanation:

Given, Length (PQ)= 10cm

Given, Breadth (QR) = 7cm  

Area of Rectangle PQRS will be = 10 * 7

                                         

                                                    = 70cm^2

Given that two semicircles of Diameter QR and PS are cut off, then

Area of remaining part will be Area of the rectangle - Area of the semicircle

Area of semicircle =  pi * r * r/2

                              = (22/7 * 3.5 *3.5 )/2

 

                              = 38.5/2

                             = 19.25cm^2

Area of two semicircles = 19.25 + 19.25

 

                                       = 38.50cm^2

Area of remaining portion = 70 - 38.50

 

                                           = 31.50cm^2

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Answer 2

Answer:

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