Question

Q) A path 1m wide is built along the border and inside a square garden of aide 30m. Find:

i) The area of path.
ii) The cost of planting grass in remaining portion at the rate of Rs 40 per sq. ​m.

Answer 1

Answer:30m-1-1=28m is the answer please follow me because I can tell you brilliant answers of your questions.

Answer 2

Step-by-step explanation:

Step-by-step explanation:

Step-by-step explanation: Let

Step-by-step explanation: Let ABCD , a square garden of side =30m.

Step-by-step explanation: Let ABCD , a square garden of side =30m.PQRS is the region inside the garden.

Step-by-step explanation: Let ABCD , a square garden of side =30m.PQRS is the region inside the garden.So,

Step-by-step explanation: Let ABCD , a square garden of side =30m.PQRS is the region inside the garden.So, PQ= (30-1-1) m =28 m

Step-by-step explanation: Let ABCD , a square garden of side =30m.PQRS is the region inside the garden.So, PQ= (30-1-1) m =28 mAlso PS = (30-1-1) m = 28 m

Step-by-step explanation: Let ABCD , a square garden of side =30m.PQRS is the region inside the garden.So, PQ= (30-1-1) m =28 mAlso PS = (30-1-1) m = 28 m

Step-by-step explanation: Let ABCD , a square garden of side =30m.PQRS is the region inside the garden.So, PQ= (30-1-1) m =28 mAlso PS = (30-1-1) m = 28 m

Step-by-step explanation: Let ABCD , a square garden of side =30m.PQRS is the region inside the garden.So, PQ= (30-1-1) m =28 mAlso PS = (30-1-1) m = 28 m (i) Area of the path = Area of ABCD - Area of PQRS.

Step-by-step explanation: Let ABCD , a square garden of side =30m.PQRS is the region inside the garden.So, PQ= (30-1-1) m =28 mAlso PS = (30-1-1) m = 28 m (i) Area of the path = Area of ABCD - Area of PQRS. = [(30×30) - (28×28)] sq.m

Step-by-step explanation: Let ABCD , a square garden of side =30m.PQRS is the region inside the garden.So, PQ= (30-1-1) m =28 mAlso PS = (30-1-1) m = 28 m (i) Area of the path = Area of ABCD - Area of PQRS. = [(30×30) - (28×28)] sq.m =900 - 784 sq.m

Step-by-step explanation: Let ABCD , a square garden of side =30m.PQRS is the region inside the garden.So, PQ= (30-1-1) m =28 mAlso PS = (30-1-1) m = 28 m (i) Area of the path = Area of ABCD - Area of PQRS. = [(30×30) - (28×28)] sq.m =900 - 784 sq.m =116 sq.m

Step-by-step explanation: Let ABCD , a square garden of side =30m.PQRS is the region inside the garden.So, PQ= (30-1-1) m =28 mAlso PS = (30-1-1) m = 28 m (i) Area of the path = Area of ABCD - Area of PQRS. = [(30×30) - (28×28)] sq.m =900 - 784 sq.m =116 sq.m( ii ) Area of the remaining portion in which the grass is planted = Area of square PQRS

Step-by-step explanation: Let ABCD , a square garden of side =30m.PQRS is the region inside the garden.So, PQ= (30-1-1) m =28 mAlso PS = (30-1-1) m = 28 m (i) Area of the path = Area of ABCD - Area of PQRS. = [(30×30) - (28×28)] sq.m =900 - 784 sq.m =116 sq.m( ii ) Area of the remaining portion in which the grass is planted = Area of square PQRS

Step-by-step explanation: Let ABCD , a square garden of side =30m.PQRS is the region inside the garden.So, PQ= (30-1-1) m =28 mAlso PS = (30-1-1) m = 28 m (i) Area of the path = Area of ABCD - Area of PQRS. = [(30×30) - (28×28)] sq.m =900 - 784 sq.m =116 sq.m( ii ) Area of the remaining portion in which the grass is planted = Area of square PQRS

= 28 ×28 sq.m

=784 sq.m

cost of planting the grass in the region PQRS

= Area × Cost = 764 × 40

= 31,360 Rs.