Q.A person wanted to distribute 96 apples and 112 orange among poor children in an orphange.He packed all the fruits in boxes in such a way that each box contains fruits of the same variety, and also every box contains an equal no. of fruits.
i) Find the minimum no. of boxes in which all fruits can be packed.
*Ans. with steps*
*No spamming*
Answers
Answered by
40
Find the H.C.F. of 96 and 112.
It'd come out to be 16. So we know, the largest number that divides both of thm is 16. Now we need to adjust them in minimum number of boxes, as per the conditions, so to keep the number of boxes minimum we need to adjust as much fruits as we can in one box, which we found out using HCF.
So, minimum number of boxes, 208/16 = 13
Hope it helps.
It'd come out to be 16. So we know, the largest number that divides both of thm is 16. Now we need to adjust them in minimum number of boxes, as per the conditions, so to keep the number of boxes minimum we need to adjust as much fruits as we can in one box, which we found out using HCF.
So, minimum number of boxes, 208/16 = 13
Hope it helps.
Answered by
11
Answer:
I think it helps.
Step-by-step explanation:
pls follow me. jacob 909
Attachments:
Similar questions