Question

Q. A wire of resistance 8-2 of length 50cm has an are of cross section 0.02 cm² . Calculate the resistivity of the wire.
class 10 physics
plyzz help me​

Answer 1

Answer:

Given:- R= 8-² ; l = 50cm ; A = 0.02cm².

R = p× l / A

p = R × A / l

p = 8-² × .02/50

p = 1 × 2/8 × 100 × 50

p = 1 / 20000

p = 0.5 × 10-4 ans

Explanation:

FOLLOW ME IF IT HELPS..

Answer 2

Explanation:

The formula of resistivity is

Resistance= (Resitivity×length)/Area

Resistance is 1/8^2 ohm and length (in m) is 0.5m

Area = 0.02/10000

1/8^2=(resistivity×5×100000)/2

1/32=500000 ×resistivity

Therefore resistivity is 16/500000

0.000032 or 6.25×10^-8 ohm m