Question

Q. Calculate the mass of constituent elements of Copper Oxide from its molecular formula CuO.​

Answer 1

Explanation:

3CuO+2NH

3

⟶3Cu+3H

2

O+N

2

3 mole 2 mole

3×80 g 2×22.4 L

= 240 g = 44.8 lit

For 240g of CuO, ammonia consumed is 44.8L

For 120gof CuO, ammonia consumed =

2

44.8

= 22.4L

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Answer 2

Explanation:

Explanation: 3CuO+2NH

Explanation: 3CuO+2NH 3

Explanation: 3CuO+2NH 3 → 3Cu + 3H

Explanation: 3CuO+2NH 3 → 3Cu + 3H 2

Explanation: 3CuO+2NH 3 → 3Cu + 3H 2 O+N

Explanation: 3CuO+2NH 3 → 3Cu + 3H 2 O+N 2

Explanation: 3CuO+2NH 3 → 3Cu + 3H 2 O+N 2 3 mole 2 mole

Explanation: 3CuO+2NH 3 → 3Cu + 3H 2 O+N 2 3 mole 2 mole 3 * 80g 2 * 22.4L

Explanation: 3CuO+2NH 3 → 3Cu + 3H 2 O+N 2 3 mole 2 mole 3 * 80g 2 * 22.4L=240 g. =44.8 lit

Explanation: 3CuO+2NH 3 → 3Cu + 3H 2 O+N 2 3 mole 2 mole 3 * 80g 2 * 22.4L=240 g. =44.8 litFor 240g of CuO , ammonia consumed is 44.8L .

Explanation: 3CuO+2NH 3 → 3Cu + 3H 2 O+N 2 3 mole 2 mole 3 * 80g 2 * 22.4L=240 g. =44.8 litFor 240g of CuO , ammonia consumed is 44.8L .For 120gof CuO, ammonia consumed =

Explanation: 3CuO+2NH 3 → 3Cu + 3H 2 O+N 2 3 mole 2 mole 3 * 80g 2 * 22.4L=240 g. =44.8 litFor 240g of CuO , ammonia consumed is 44.8L .For 120gof CuO, ammonia consumed = 2

Explanation: 3CuO+2NH 3 → 3Cu + 3H 2 O+N 2 3 mole 2 mole 3 * 80g 2 * 22.4L=240 g. =44.8 litFor 240g of CuO , ammonia consumed is 44.8L .For 120gof CuO, ammonia consumed = 2 44.8

Explanation: 3CuO+2NH 3 → 3Cu + 3H 2 O+N 2 3 mole 2 mole 3 * 80g 2 * 22.4L=240 g. =44.8 litFor 240g of CuO , ammonia consumed is 44.8L .For 120gof CuO, ammonia consumed = 2 44.8 =22.4L

Explanation: 3CuO+2NH 3 → 3Cu + 3H 2 O+N 2 3 mole 2 mole 3 * 80g 2 * 22.4L=240 g. =44.8 litFor 240g of CuO , ammonia consumed is 44.8L .For 120gof CuO, ammonia consumed = 2 44.8 =22.4L Mark as brainliest and thanks me