Question

Q. Calculate the number of atoms of hydrogen present in 5.6
g of urea (NH2)2CO​

Answer 1

Answer:

Solution. Now, 1 molecule of urea has total of 8 atoms, out of which 4 atoms are of H, 2 atoms are of N, 1 of C, and 1 of O. 5.6 g of urea contains 2.247 × 1023 atoms of H, 1.124 × 1023 atoms of N, 0.562 × 1023 atoms of C, and 0.562 × 1023 atoms of O.

Explanation:

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