Chemistry, asked by rdange489, 1 day ago

Q. Calculate the number of atoms of hydrogen present in 5.6 g of urea, (NH,),CO. Also calculate the number of atoms of N, C and O. (Ans. : No. of atoms of H = 2.24 x 1023 N=1.124 x 1023 and C = 0.562 x 1023, O = 0.562 x 1023)

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Answered by saifiilma084

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Calculate the number of atoms of hydrogen present in 5.6 g of urea, (NH2),CO. Also calculate the number of atoms of N, C and O. (Ans. : No. of atoms of H = 2.24 x 1023, N=1.124 x 1023 and C=0.562 x 1023, O = 0.562 x 1023) hc.

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Q. Calculate the number of atoms of hydrogen present in 5.6 g of urea, (NH,),CO. Also calculate the number of atoms of N, C and O. (Ans. : No. of atoms of H = 2.24 x 1023 N=1.124 x 1023 and C = 0.562 x 1023, O = 0.562 x 1023)​

Answers

Q. Calculate the number of atoms of hydrogen present in 5.6 g of urea, (NH,),CO. Also calculate the number of atoms of N, C and O. (Ans. : No. of atoms of H = 2.24 x 1023 N=1.124 x 1023 and C = 0.562 x 1023, O = 0.562 x 1023)