Physics, asked by Csilla, 2 days ago

Q] Certain quantity of water cools from 70°C to 60°C in the first 5 min and to 54°C in the next 5 min. The temperature of the surrounding is​

Answers

Answered by itzstylishbandi
5

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Certain quantity of water cools from 70°C to 60°C in the first 5 min and to 54°C in the next 5 min. The temperature of the surrounding is

\small \underbrace \mathfrak \red{ANSWER }

 \frac{60 - 70}{5}  = k(65 - t)

 \frac{54 - 60}{5}  - k(57 - t)

 \frac{ - 10}{ - 6}  =  \frac{65 - t}{57 - t}

285 - 5t =  195 - 3t

90 = 2t

t = 45

Answer:

T=45°

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Answered by Rockstar9086
1

Here is your Answer buddy..

Hope it helps...

ur intro..

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