Question

Q. ( cosec theta - cot theta )whole square = 1- cos theta/ 1+ cos theta​

Answer 1

Answer:

Cosec²Ø–2CosecØCotØ+Cot²Ø

= 1/Sin²Ø–(2×CosØ)/Sin²Ø+Cos²Ø/Sin²Ø

= 1/Sin²Ø {1–2CosØ+Cos²Ø}

= 1/Sin²Ø(1–CosØ)²

= (1–CosØ)²/Sin²Ø

= (1–CosØ)²/(1–Cos²Ø)

= (1–CosØ)²/{(1)²–(CosØ)²}

= (1–CosØ)²/{(1+CosØ)(1–CosØ)}

= (1–CosØ)/(1+CosØ) (proved)