Question

Q. Find kinetic energy of 0.05 mole of an ideal gas at
273 K.
(a) 1702.2 J
(b) 170.22 J
(c) 17.022 J
(d) 34.44 J
​

Answer 1

Explanation:

option (a) is right answer

Answer 2

Answer:

Option A is the right answer

Explanation:

According to the formula

For average kinetic energy of ideal gases is

KE=3/2nRT

Where,

n=Number of moles of the gas

R=Gas constant

T=Temperature in K.

S0,

KE=  3 /2 ×0.5×8.3145×273   = =1702.4 J

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