Question

Q) Find the area of the following triangles :-

Please give step by step answer.

Thank You. ​

Answer 1

Question:-

Find the area of triangle given in the diagram:-

Answer:-

• The area of triangle is 78 cm²

To find:-

• Area of triangle

Solution:-

Here,

• AD = Height of triangle = 12 cm
• BC = Base of triangle = 13 cm

We have to find the area of triangle.

As we know,

$\large{ \boxed{ \mathfrak{area = \frac{1}{2} \times b \times h}}}$

Where,

• b = base of triangle
• h = height of triangle

According to question,

$\large{ \tt : \implies \: \: \: \: \: \: area = \frac{1}{2} \times 12 \times 13}$

$\large{ \tt : \implies \: \: \: \: \: \: area = 6 \times 13}$

$\large{ \tt : \implies \: \: \: \: \: \: area = 78 \: {cm}^{2} }$

Hence,

• The area of triangle is 78 cm².

Answer 2

Given:-

• Base of the triangle is 13 cm.
• Height of the triangle is 12 cm.

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To find:-

• Area of the triangle.

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Solution:-

★Formula used:-

$\star{\boxed{\sf{\orange{Area\: of\: triangle = \dfrac{1}{2} \times base \times height}}}}$

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$\tt\longmapsto{\dfrac{1}{2} \times b \times h}$

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$\tt\longmapsto{\dfrac{1}{2} \times 13 \times 12}$

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$\tt\longmapsto{\dfrac{1}{2} \times 156}$

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$\tt\longmapsto{\boxed{\red{78\: cm^2}}}$

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Hence,

• the area of the triangle is 78 cm².

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★More to know :-

$\sf{Area\;of\;Rectangle\;=\;Length\;\times\;Breadth}$

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$\sf{Area\;of\;Square\;=\;(Side)^{2}}$

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$\sf{Area\;of\;Triangle\;=\;\dfrac{1}{2}\;\times\;Base\;\times\;Height}$

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$\sf{Area\;of\;Parallelogram\;=\;Base\;\times\;Height}$

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$\sf{Area\;of\;Circle\;=\;\pi r^{2}}$

$\sf{Perimeter\;of\;Rectangle\;=\;2\;\times\;(Length\;+\;Breadth)}$

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$\sf{Perimeter\;of\;Rectangle\;=\;4\;\times\;(Side)}$

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$\sf{Perimeter\;of\;Circle\;=\;2\pi r}$