Question

Q. Find the perimeter of each of the following shapes:
(i) An equilateral triangle of side 9 cm.
(ii) An isosceles triangle with equal side 8 cm each and third side 6 cm.
(iii) An isosceles triangle ABC, with AB = AC = 10 cm and altitude from A on
BC equal to 8 cm
(iv) A regular hexagon with each side measuring 8 em.​

Answer 1

Step-by-step explanation:

PERIMETER= SUM OF ALL SIDES

1) EQUILATERAL TRIANGLE

=9+9+9=27cm

2)ISOSCELES TRIANGLE

=8+8+6=22cm

3)USE PYTHAGORAS THEROM,

(10)^2-(8)^2=36=6^2

SO 3RD SIDE WILL BE 2×6=12cm

SO PERIMETER WILL BE 10+10+12=32cm

4) PERIMETER OF REGULAR HEXAGON

=8×6=48CM

Answer 2

Answer:perimeter of an isosceles triangle=8+8+6=22 cm

solutionperimeter of an isosceles triangle=8+8+6=22 cm

solutionperimeter of an isosceles triangle=8+8+6=22 cm

solutionperimeter of an isosceles triangle=8+8+6=22 cm

solutionperimeter of an isosceles triangle=8+8+6=22 cm

solutionperimeter of an isosceles triangle=8+8+6=22 cm

solutionperimeter of an isosceles triangle=8+8+6=22 cm

solutionperimeter of an isosceles triangle=8+8+6=22 cm

solutionperimeter of an isosceles triangle=8+8+6=22 cm

solution

Step-by-step explanation: