Question

Q.Find the surface area and volume of a solid in the form of right circular cylinder with hemisperical end if the whole length is 22 cm and radius of the cylinder is 3 cm.
$take \: \: ( \pi = 3.14)$
NO SPAMMING!!!​

Answer 1

Answer:

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Answer 2

$\huge\mathtt\orange{Solution:-}$

Let r & h be the radius & height of the Cylinder respectively.

So,

r = 3cm

h = 22-2(3)=16cm

$\:$

Volume of solid = Volume of Cylinder + volume of two hemispheres.

$= \pi \: r {}^{2} h + 2 (\frac{2\pi}{3} r {}^{3} )$

$= \pi \times {3}^{2} \times 16 + \frac{4\pi}{3} \times {3}^{3}$

$= 565.71 \: {cm}^{3}$

TSA = CSA of Cylinder + SA of two hemispheres

$= 2\pi \: rh + 2(2\pi {r}^{2} ) \\ = 2\pi \: r(h + 2r)$

$= 2\pi \times 3(16 + 6)$

$= 6 \times 3.14 \times 22$

$= 414.85 \: cm {}^{2}$

$\:$

Note: π Taken as 3.14.